
we can try n = 1 and see if -27 is the output
(1) 15 – 27(1)
(2) 15 – 27(1 – 1)
(3) – 27 + 15(1)
(4) – 27 +15(1 – 1)
Category Archives: #mtbos
Get the Math and the Points Aug 2018 CC Alg I Regents #19

The two red marks are where f(x) = g(x), neither of which lie on the axes.
The x-intercepts would be on the x-axis and the y-intercepts would be on the y-axis.
The other clue is that solutions are x values.
Get the Math and the Points Aug 2018 CC Alg I Regents #18

Try each point – we are looking for the one that does not work — that makes the equation untrue:
For x = -2 and y = 10: 3(10) + 2 = (-2)^2 – 5(-2) + 17
For x = -1 and y = 7: 3(7) + 2 = (-1)^2 – 5(-1) + 17
For x = 2 and y = 3: 3(3) + 2 = (2)^2 – 5(2) + 17
For x = 5 and y = 5: 3(5) + 2 = (5)^2 – 5(5) + 17
Get the Math and the Points Aug 2018 CC Alg I Regents #17

30 is the fixed cost and 2.40 is the variable cost (per dog)
so read really carefully
Get the Math and the Points CC Algebra I Aug 2018 #16

This is asking for factored form. We can take the factored form and double distribute aka FOIL to see if that algebra is equivalent to what was given.
Also, the original can be put into Y1 and each of the algebra in the answers can be put into Y2, then compare Y1 and Y2 to check your answer.