This question asks students to substitute or plug in -3 for x so

g(-3) = -2(3)^2 + 3(-3) being careful about order of operations 🙂

Students can check their work by using the TI-84

This question asks students to substitute or plug in -3 for x so

g(-3) = -2(3)^2 + 3(-3) being careful about order of operations 🙂

Students can check their work by using the TI-84

Dear New York High Schoolers,

Best on your Regents exams this week.

Make sure you get to school early and eat a good breakfast!

Do not leave early: Spend all the allotted time (3 hours — unless your IEP is for more time)

Eat a good breakfast

Read carefully

Go over the entire exam after you finish and check your work

Sincerely,

Robin the Math Lady

The left hand side of the equation is almost a perfect square:

In order for it to be a perfect square: x^2 + 4x + ____ = 2 + ____

To find the number that completes the square take 1/2 of 4 and square it

So 4 gets added to both sides

Then the right side becomes 6

Then we can write the left side like this: (x + 2) ^2

So (x + 2)^2 = 6

then take the sqrt of both sides but do not forget the +/- with the sqrt

Then subtract 2 from both sides:

You will have two answers a plus and a minus and you can check your work by using the quadratic formula 🙂

To solve a quadratic equation ax^2 + bx + c = 0, wecan use the quadratic formula above given on the Regents Reference Sheet.

In order to find out if a solution is rational or irrational, we focus on the algebra under the radical: b^2 – 4ac: If b^2 – 4ac is a perfect square, then when we take the square root, we will get a rational number but if b^2 – 4ac is not a perfect square (like 4, 9, 16 etc), then the solution will be irrational.

In the equation 2x^2 + 3x – 10 =0, a=2, b=3 and c = -10

Once you substitute in those numbers into b^2 – 4ac, do you get a perfect square or not?

Average rate of change is another name for slope

(big hint given in the units feet per second).

Slope is change in y / change in x — the slope formula is (y2 – y1)/(x2 – x1)

Use the two points (3, 6.26) and (9, 3.41) for (x1, y1) and (x2,y2).

Show your work. Because 3.41 is less than 6.26, your answer should be negative.