1 x 4 rectangles: 2
24 rectangles (no double counting of squares as rectangles)total of 40
Q: A Math quiz has 
multiple-choice questions, each with choices. A student passes the quiz with 
or more correct questions. If the student randomly picks their answers, what is the probability of passing the quiz?
A: 7/27 = 1/27 + 6/27
Scenario 1: The student gets all 3 correct (1/3) x (1/3) x (1/3) = 1/27
Scenario 2: The student gets 2 correct. 1/3 x 1/3 x 2/3 but this can happen 3 different ways as the student could get the 1st one incorrect or the 2nd or the 3rd.
so (1/3)x (1/3) x (2/3) x 3 = 6/27
1/27 + 6/27 = 7/27.
Factoring out 2^2016 from both the numerator and the denominator:
results in 5/3.
If a point aka ordered pair is a solution, it will appear on the table as the (x,y) will make the equation true.
Check all the “easy” x values that are integers (x = 0, x = 5, x = -1) — which y value in the answer choice does not match that of the table?
Look at where the graph crosses the x axis…then check those x values by seeing that the y value is 0 on the table. Students can also prove their answer by substituting the x values into the equation to see if the result is 0.
