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Get the Math and Points June 2017 CC Alg I Regents #8

June 2017 CC Alg I 8

Using substitution, we can rewrite the second equation as
3(-2x + 2x + 8) = 12
3(8) = 12
24 = 12
huh?  NO solution

If we were to solve the second equation for Y=, we would get:
by distributing the 3
-6x + 3y = 12
add 6x to each side
3y = 6x + 12
Divide both sides by 3
y = 2x + 4 this is parallel to the first line y = 2x + 8 and therefore the lines will never meet
making the answer “No solution”

 

 

 

 

 

 

 

Get the Math and Points June 2017 CC Alg I #7

June 2017 CC Alg I 7
First look at the graph — looks super nonlinear and pretty exponential
Use the point (0,4).
We can eliminate answers (2) and (3), as if we substitute h=0,  the output would be 6/5 and 4.2 as opposed to the 4 for the y value we are looking for.
Now we can use the point (1,8) to see if y = 8 when x = 1
For answer (4), if we substitute in x = 1, we get 2/3(1)^3 – 1^2 + 3(1) + 4 = 2/3 – 1 + 3 + 4≠ 8
Try answer (1): using order of operations: 4(2)^1 = 4(2) = 8
4(2)^2 = 16 and 4(2)^3 = 32.  That’s it –2 points
You can also use Y= and check the table for a match: