

Q: A swindler showed an honest man a six sided die. If the man rolled a ONE, he wins, and gets back twice the amount of his bet. If not, the swindler keeps the bet. “But…my chances are only one out of six,” retorted the man. “True,” grinned the swindler, “But I’ll give you three tries to get a one.” The man considered if I have 3 tries, each try has a 1/6 chance of winning, so my chances of winning are 3/6 or 1/2. Is the bet really fair? If not, what are the chances of the man winning?
A: 91/216
You cannot just add 1/6 + 1/6 +1/6 so 1/2 is incorrect. The probability of not getting a 1 is 5/6 (there are 6 sides and the other possible outcomes are 2, 3, 4, 5 or 6). The probability of no 1s in 3 throws is 5/6 x 5/6 x 5/6 = 125/216 which is the probability of the swindler winning. So the probability of the man winning is 1 – 125/216 = 216/216 – 125/216 = 91/216.


Pre-Uber it was Integrated Algebra, see below for current freshman-year algebra
Common Core Algebra I Regents

Pre-Uber, was getting a cab in NYC harder than freshman-year algebra?
Please vote HERE
Glad to see the Math in the tag line “Helping aggrieved consumers for more than six-tenths of a decade”
“The rule for the square of a binomial”: Spotted with a 12th grader Homework on Pearson’s My Math Lab
Should we tell students exactly what to do?
Categorization is one of the most important skills in Math and one of the most important takeaways for future Math classes and in general.
The question above creates teaching and learning questions:
“Should we tell students what to do based on rules?”
“Can students (even) remember rules?”
“What would be the answer to this problem?”

Helping students with homework can be easier with examples rather than rules.
10 times as much as vs. 1/10 of can be clarified by using better numbers:
so we chose 6 as our better number
6 is 10 times as much as 0.6 and 1/10 of 60
Now we know how to answer each column by comparing it to our easy example of 6!!