This is a classic probability question. Once you know that one coin is a head, there are 3 possible outcomes for the two coins with at least one head.

HH

HT

Q: Two coins are flipped and you cannot see the outcome but are told that at least one is a head. What is the probability that the other coin also landed on heads?

A: 1/3

This is a classic probability question. Once you know that one coin is a head, there are 3 possible outcomes for the two coins with at least one head.

HH

HT

This is a classic probability question. Once you know that one coin is a head, there are 3 possible outcomes for the two coins with at least one head.

HH

HT

TH

Since you know that one is a heads, and there are 3 possible outcomes, the probability is 1/3.

Q: Write down all the integers from 1 through 60 to form the number

123456789101112131415161718…495051525354555657585960.

Now delete 100 digits from this number.

Without rearranging the digits, what is the largest number possible?

A: Writing down all integers from 1 through 60 gives you a number 111 digits long:

9 numbers at 1 digit apiece: 9 digits

51 numbers at 2 digits apiece: 102 digits

Total: 111 digits.

If we’re not allowed to rearrange the digits, the largest number is:

99 999 785 960.

Write the numbers from 1 to 8 into the squares, so that the squares with consecutive numbers do not touch

(neither edges nor corners).

(neither edges nor corners).

Here is one version of a correct answer:

such as the whole grid can be upside down (64 on top and 53 on bottom)

or it can be reversed left to right.

Q: Find the three digit number that when you multiply it by two, it is one more than the reverse of the original number.

For example, 102 doubled is 204 which is 3 more than the reverse (201).

A: 397

Q: MAD + AS + A = BULL

Each letter stands for a number 0 -9 but not all digits will be used.

Each letter stands for a number 0 -9 but not all digits will be used.

If D = 3 and L = 7, find the value of the other letters

A:

983 + 86 + 8 = 1077

writing it vertically helps a lot

The B has to be a 1 as the total would be over 1000 and the M has to be a 9 as we are only adding a two digit and 1 digit number and getting over 1000

the last column must be adding up to 17 rather than 7 (otherwise S + A would be 4 and would be 1 and 3 but 3 is already used)

so S + A = 14 and since there will be a carry the next column over A + A + 1 will equal 17

so A = 8 and therefore A = 6